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REGEXPR_SUBSTR returning too much data

5 replies [Last post]
Thu, 11/08/2012 - 7:30pm
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I'm trying to use REGEXPR_SUBSTR to return ONLY the data after the = sign in my string. For example, the string is T34XH5=170. I only want 170. I can't figure out how to strip out the =. I have tried several iterations. My current one is:

REGEXP_SUBSTR('T34XH5=170','=[^FINAL]+')
What I get is =170. I just need 170. ?

I've also tried:
REGEXP_SUBSTR('T34XH5=170','=[^ ]') and get the same result.

My SQL skills are pretty remedial so I'm kind of grasping here.
Thanks!
M

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Thu, 11/08/2012 - 7:31pm
#1
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Guest
Re: REGEXPR_SUBSTR returning too much data

Sorry.....that's REGEXP, not REGEXPR. See how remedial I am!!! :)

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Tue, 12/11/2012 - 6:13am
#2
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Guest
Re: REGEXPR_SUBSTR returning too much data

Hiya,

Instr func should get you that, I do guess so....

Else give this a try,

SELECT SUBSTR('T34XH5=170.',8,12) FROM DUAL

Thanks,
RKO

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Fri, 03/23/2018 - 2:39pm
#3
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Guest
Re: REGEXPR_SUBSTR returning too much data

Regexp_Substr('T34XH5=170', '\d{3}')

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Fri, 03/23/2018 - 2:41pm
#4
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Re: REGEXPR_SUBSTR returning too much data

Regexp_Substr('T34XH5=170', '[^/=]+', 1, 2)

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Fri, 03/23/2018 - 2:50pm
#5
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Guest
Re: REGEXPR_SUBSTR returning too much data

Regexp_Substr('T34XH5=170', '=(.*)', 1, 1, 'i', 1)

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